error message, when i edit in php
edit.php
-: EDIT FORM :-
EDIT DATA
<?php
include("/includes/database.php");//database connection
/* $continued = mysql_connect("localhost","root","OtlPHP07");
mysql_select_db("employees");*/
?>
<?php
//$employee_number = $_GET["id"];
$order = "SELECT * FROM data_employees order by employee_number";
$result = mysql_query($order);
while ($row=mysql_fetch_array($result)){
echo ("<tr><td>$row[name]</td>");
echo ("<td>$row[employee_number]</td>");
echo ("<td>$row[address]</td>");
echo ("<td><a href=\"edit_form.php?id=$row[employee_number]\">Edit</a></td></tr>");
}
?>
edit_form.php
Form Edit Data
Form Edit Employees Data
<?php
include ("/includes/database.php");//database connection
//mysql_connect("localhost","user","OtlPHP07");
//mysql_select_db("employees");
?>
<?php
$order = "SELECT * FROM data_employees WHERE employee_number='$id'";
$result = mysql_query($order);
$row = mysql_fetch_array($result);
?>
Name
Address
edit_data.php
<?php
//edit_data.php
include ("/includes/database.php");
$order = "UPDATE data_employees
SET name='$name',
address='$address'
WHERE
employee_number='$id'";
mysql_query($order);
header("location:edit.php");
?>
paratan posted this at 11:46 — 7th June 2013.
They have: 1 posts
Joined: Jun 2013
whe you trying to echo i.e.
echo ("<tr><td>$row[name]</td>");
do not place variable inside the double quotes .Text other than variable should be inside quotes and it should be concatenated with variable. so, the proper format is :echo("<tr><td>".$row[name]."</td></tr>");
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