trying to get returns on html docs
I get this error:
Quote: Parse error: parse error, expecting `T_WHILE' in /home/ememi/ememi-www/tmp/catch.php3 on line 11
from a page containing this code:
<html><body>
<?php $db = mysql_connect("localhost", "ememi", "password");
mysql_select_db("mydb",$db);
$result = mysql_query("SELECT recipes FROM RECIPES where ing1='cheese'",$db);
do while ($myrow = mysql_fetch_row($result))
{printf("recipes: %s<br>\n",$myrow[0]);}?>
</body></html>when I run this inside the interface provided by my host, I get a return - does anyone recognize this? - thanks
[Edited by mmi on Jan. 28, 2001 at 11:57 PM]
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Mark Hensler posted this at 04:47 — 29th January 2001.
He has: 4,048 posts
Joined: Aug 2000
hehehe, I've done this myself before. You program VB or ASP, don't you. do while is a VB or ASP function. The PHP equivalent is while (not 'do').
How's that for turn around time?
Good Luck,
(Peter, close mmi's [ code ])
Mark Hensler
If there is no answer on Google, then there is no question.
mmi posted this at 04:53 — 29th January 2001.
They have: 457 posts
Joined: Jan 2001
what took ya so long
- this is weird - I get no display in N4.72 for this page although the code is there on view - in IE, I get a strange-lookin' black-and-white box - I guess I didn't close the "code" tag - anyway, thanks a lot - I may have MANY similar questions 
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mmi posted this at 05:03 — 29th January 2001.
They have: 457 posts
Joined: Jan 2001
I originally used "while" but that gets me
Warning: Supplied argument is not a valid MySQL result resource in /home/ememi/ememi-www/tmp/catch.php3 on line 9
let me quickly disabuse you of the notion that I program in ANY language!!
- thanks for your help
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Mark Hensler posted this at 07:22 — 29th January 2001.
He has: 4,048 posts
Joined: Aug 2000
Because I develope many pages that use the same database, I write one connection string, put it in a function, and in its own file. Then, anywhere I need to connect to that DB, I include "db_name.php" and run db_connect(). If I ever move the database to another server, change username/passwords, or anything else, I can fix everything in that one page.
try this instead:
function db_connect () {
## In the line below, insert: ("host", "ememi", "password"); ##
$link = mysql_pconnect ("host", "user", "password");
## In the line below, insert ("your_database_name") ##
if ($link && mysql_select_db ("mydb")) {
return ($link);
}
else {
return (FALSE);
}
}
/* blah (more code) blah */
db_connect()
or die("Error connecting to database");
$result = mysql_query("SELECT recipes FROM RECIPES where ing1='cheese'");
do while ($myrow = mysql_fetch_row($result))
{printf("recipes: %s<br>\n",$myrow[0]);}
you only need the $db if you plan on having more than one DB connection at the same time. In which case, the code would look like this:
$db = db_connect()
or die("Error connecting to database");
$result = mysql_query("SELECT recipes FROM RECIPES where ing1='cheese'",$db);
The only problem in the code you provided (other than the 'do') was that you forgot to set $db equal to a database link (mysql_select_db("mydb",$db)
(same day delivery, lol)
Good Luck,
Mark Hensler
If there is no answer on Google, then there is no question.
mmi posted this at 08:04 — 29th January 2001.
They have: 457 posts
Joined: Jan 2001
SUCCESS - got a return!!!
recipes: Crescent Brie with Almonds
recipes: Gougères (Cheese Puffs)
recipes: Pita and Cheese Toasts
recipes: Cheese Straws
honestly can't thank you enough - you've given me a big boost when I really needed one - (I was pullin' for the Gnats
) - I'll likely be back for help formatting this return :eek: - THANKS!! THANKS!! THANKS!!
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mmi posted this at 18:45 — 1st February 2001.
They have: 457 posts
Joined: Jan 2001
can anyone help me get started on troubleshooting this?
<html><head><title>PHP/SQL Test 2</title>
<STYLE TYPE="text/css"><!--
BODY {font: 10pt Tahoma; color: #000080}
SPAN {font: 500 14pt Tahoma; color: #f4c508}
--></STYLE>
<body background="images/bback1.jpg" bgcolor="#ffffff" text="#000000" leftmargin="0"
topmargin="0" marginwidth="0" marginheight="0" id=all>
<?php $db = mysql_connect("localhost", "ememi", "password");
mysql_select_db("ememi_com",$db);?>
<SPAN>ALL RECIPES</SPAN><BR>
<?
$result = mysql_query("SELECT * FROM recipes",$db);
while ($row = mysql_fetch_array($result))
{
//INFO IS IN AN ARRAY CALLED $row. $row[0] IS THE FIRST COLUMN, $row[1] IS THE SECOND COLUMN, AND SO ON.
?>
<table>
<tr>
<td><a href="<? echo $row[4]; ?>"><? echo $row[0]; ?></a></td>
</tr>
<tr>
<td>Ingredients for this recipe are: <? echo "$row[1],$row[2],$row[3]"; ?><td>
</tr>
</table><br>
<?
}
?>
</body></html>
this is line 22
while ($row = mysql_fetch_array($result))'ThanksWeb Xpertz Community Forums for Webmasters & Developers
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Mark Hensler posted this at 21:39 — 1st February 2001.
He has: 4,048 posts
Joined: Aug 2000
Your syntax looks fine. Make sure that the table 'recipes' exists in the 'ememi_com' database. Check your username/password.
Try this to check all your connections stuff....
<?
$db = mysql_connect("localhost", "ememi", "password");
if ($db && mysql_select_db("ememi_com",$db)) {
//all is well..
}
else {
die("Error connecting to database");
}
?>
Good Luck,
Mark Hensler
If there is no answer on Google, then there is no question.
mmi posted this at 21:47 — 1st February 2001.
They have: 457 posts
Joined: Jan 2001
oh yeah, RECIPES is in there - and I just use "password" to substitute for my maximum-security ultra-secret REAL password :eek: - I really appreciate you helping me with this - I have no real clue as I said before
- THANKS!!! - I may be back for formatting help so better let the machine pick up, if ya know what I mean 
btw, here's the page - guess you're kind of a godfather 
-----------
hold on - I may have it
-----------
you're a gentleman and a programmer - you hit it right on, buddy - the db is "RECIPES" not "recipes" - believe it or not I kinda recognize the error message now - I oughta recognize 'em - I see 'em often enough
[Edited by mmi on Feb. 01, 2001 at 05:04 PM]
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Mark Hensler posted this at 09:14 — 2nd February 2001.
He has: 4,048 posts
Joined: Aug 2000
anytime... glad I could help!
[formating is fun... ;)]
mmi posted this at 19:09 — 2nd February 2001.
They have: 457 posts
Joined: Jan 2001
ok, counselor, time to move in for the...creation - I wanna use this db in a search engine on this page - [grab some popcorn, hit search and enjoy the film!! - off-center because it's outside its pop-up window] - as usual, I'm clueless here and basically just looking to get started in the right direction - like a framework / gameplan - I want to generate a list of links to recipes containing an ingredient typed into the textbox by a viewer - here's the code I have so far
<html><head><title>PHP/SQL Test 2</title>
<STYLE TYPE="text/css"><!--
BODY {font: 10pt Tahoma; color: #000080}
SPAN {font: 500 14pt Tahoma; color: #f4c508}
--></STYLE>
<body background="images/bback1.jpg" bgcolor="#ffffff" text="#000000" leftmargin="0"
topmargin="0" marginwidth="0" marginheight="0" id=all>
<?php $db = mysql_connect("localhost", "ememi", "password");
mysql_select_db("ememi_com",$db);?>
<SPAN> ALL RECIPES</SPAN><BR>
<?
$result = mysql_query("SELECT * FROM RECIPES",$db);
while ($row = mysql_fetch_array($result))
{
//INFO IS IN AN ARRAY CALLED $row. $row[0] IS THE FIRST COLUMN, $row[1] IS THE SECOND COLUMN, AND SO ON
?>
<table>
<tr>
<td><a href="<? echo $row[5]; ?>" target="Introduction"><? echo $row[1]; ?></a></td>
</tr>
<tr>
<td>
<table>
<tr><td valign="top">keyword(s):</td>
<td><? echo $row[2]; ?><br>
<? echo $row[3]; ?><br>
<? echo $row[4]; ?></td></tr>
</table></td>
</tr>
</table><br>
<?}?>
</body></html>
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Mark Hensler posted this at 04:50 — 3rd February 2001.
He has: 4,048 posts
Joined: Aug 2000
thx for the screen shot, it helps to visualize where I'm pulling from...
here is some ruff code..
<!-- results page: results.php-->
<html>
<body bgcolor="#ffffff" text="#000000" id=all>
<?
$db = mysql_connect("localhost", "ememi", "password");
mysql_select_db("ememi_com",$db);
$query = "SELECT * FROM RECIPES WHERE (ing1 LIKE '%$ingrediant%') OR (ing2 LIKE '%$ingrediant%') OR (ing3 LIKE '%$ingrediant%')";
$result = mysql_query($query,$db);
while ($recipe = mysql_fetch_array($result))
{
?>
<table>
<tr>
<td><a href="<? echo $recipe[href]; ?>" target="Introduction"><? echo $recipe[recipe]; ?></a></td>
</tr>
<tr>
<td>
<table>
<tr><td valign="top">keyword(s):</td>
<td><? echo $recipe[ing1]; ?><br>
<? echo $recipe[ing2]; ?><br>
<? echo $recipe[ing3];?></td></tr>
</table></td>
</tr>
</table>
<br>
<?
} #END while
?>
</body></html>
<!--input search page: search.php--><html>
<body bgcolor="#ffffff" text="#000000" id=all>
<form action="results.php" method=POST>
<input type=text name=ingrediant><BR>
<input type=submit value="Go get it!">
</form>
</body>
What's happening...
A % in the query is a wild card. So I put a % before and after the ingrediant that the user is looking for. This way they can enter 'berry' and get results on 'blue berry' or 'raspberry'... If you want an exact phrase, take out all %.
Also note the way I handle the mysql_fetch_array... I have it assigned to $recipe. What I want to point out is that I am not using numbers to address fields. I am using the field name. To read more about this, click here.
Mark Hensler
If there is no answer on Google, then there is no question.
mmi posted this at 06:31 — 3rd February 2001.
They have: 457 posts
Joined: Jan 2001
definite progress, my friend - when ya type an ingredient (say, "cheese"
) into this page, there's the recipes with cheese as an ing!!! - I think maybe the best thing for me to do (to preserve forum capital if nothing else) is to play around with this new toy you've handed me to see if I can format it up the way I picture it in my mind (can't let you have ALL the fun 
) - I may get nowhere and almost certainly won't get to the final destination without more indispensible help, so I'm sure I'll be back - btw, my brother is an overpaid underworked Oracle dba who says he can't help me much ("sorry, I don't program anymore" - makes sense - he seems to just sit around waiting for systems that never fail to...ah...fail 
) and who MAY decide I'm no longer just a "worthless commie troublemaker" when I show him this - then I'll tell him it's just another triumph for "real" socialism - the kind practiced in a wonderful community like this forum by friendly, helpful, knowledgable people like you - HA!! take THAT ya country-clubber!!! 
THANKS!!! THANKS!!! THANKS!!!
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mmi posted this at 07:04 — 3rd February 2001.
They have: 457 posts
Joined: Jan 2001
can ya give me one more on this (so much for that "lemme do it myself talk
) - I can't figure out howta get the titles to come up in the return - anything???
-------
hold on - may have an idea
-------
nope - nuthin'
-------
seem to have it now!!!
[Edited by mmi on Feb. 03, 2001 at 02:10 AM]
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Mark Hensler posted this at 07:55 — 3rd February 2001.
He has: 4,048 posts
Joined: Aug 2000
LOL!! so, does it work now?
I would love to get paid to just sit around waiting...
mmi posted this at 07:55 — 3rd February 2001.
They have: 457 posts
Joined: Jan 2001
go to Cooking My Way
click on "index" in the navbar
type in an accepted keyword, e.g., cheese
voilà!!
just need to set up a timeout to let the apple spin for a couple 'a seconds - I'm kinda concerned though cuz when I try to put the code back the way it was the movie displays but it's static
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mmi posted this at 01:29 — 6th February 2001.
They have: 457 posts
Joined: Jan 2001
well, here's one - how would I direct viewers to a page that says "sorry, nuthin' on that"? -I'm wonderin' if this is gonna be complicated by the use of LIKE - I know a little about db's and SQL and I'm guessing that working out the final details on this may get complicated - thanks
apparently 
---------
do I wanna test to see if the return on ingredient is null and then print a string? - is this something to be handled in SQL, PHP, js? - easily
[Edited by mmi on Feb. 06, 2001 at 12:58 AM]
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Mark Hensler posted this at 06:32 — 6th February 2001.
He has: 4,048 posts
Joined: Aug 2000
Make this change to the query string....
// old
$query = "SELECT * FROM RECIPES WHERE (ing1 LIKE '%$ingrediant%') OR (ing2 LIKE '%$ingrediant%') OR (ing3 LIKE '%$ingrediant%')";
// new
$query = "SELECT * FROM RECIPES WHERE (ing1 LIKE '%$ingrediant%') OR (ing2 LIKE '%$ingrediant%') OR (ing3 LIKE '%$ingrediant%')";
$query .= " AND (ing1 IS NOT NULL) AND (ing2 IS NOT NULL) AND (ing31 IS NOT NULL)";
then, check to see if you have any results....
if (mysql_num_rows($result) == 0) {
// "Sorry nuthin' on that"
}
while ($recipe = mysql_fetch_array($result) {
// if there are no rows returned, this part will never be used
// so don't bother putting this in an IF statement
// blah (do your loop thing here) blah
}
Mark Hensler
If there is no answer on Google, then there is no question.
mmi posted this at 07:40 — 6th February 2001.
They have: 457 posts
Joined: Jan 2001
thanks a lot
- I'll see what I can make 'a that mess after my nightly nap 
- Produce Theater Productions is apparently gettin' struck by the Teamsters at the moment - just wonderin', you got any ideas on how to get my flippin' apple integrated into this? - I've been advised to move it from the "search" page to the "results" page? - does that seem more workable to you?
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mmi posted this at 17:22 — 6th February 2001.
They have: 457 posts
Joined: Jan 2001
this is great!! HOWEVER
, how should I try to handle the lollowing? - if ya type in, say, "parsnip", I get the response I want - but is there any way to better manage an entry like "pa"? - right now I get Lasagna cuz it's got pasta and a chicken dish that features paprika - is a return like this the price I MUST pay for using the wildcards or is there a way to limit things and get a more "reasoned" response? btw, I suppose I'll be at least morally obligated to credit your contribution to CMW - or would that be an honor of dubious distinction? 
----------
guess I'll hafta dig out my Oracle / SQL books :eek:
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Mark Hensler posted this at 07:47 — 8th February 2001.
He has: 4,048 posts
Joined: Aug 2000
I'm not sure what you want to do. What do you want "pa" to return? nothing?
you can do a strict search by taking out the wildcards. So "pa" will not return anything, and "salt" will only match "salt" and not "saltines".
If you want you could get even wilder, and allow the user to choose 'partial word' matches, 'exact phrases', or 'any word'.
Example... search criteria: "apple pie"
Partial word would break up the spaces and search for anything with "apple" or "pie" in it. This could return "apple", "pie", "apple pie", and "pineapple".
Exact phrase would search for just that... the exact phrase. and return only "apple pie".
Any word would split the spaces and search for "apple" or "pie". And return "apple", and "pie". But not "pineapple"
If you want a search that powerful, it will require a bit of ASP coding. So make a new post in the 'Other Scripting Languages Help Forums'.
I'm drawing a blank... what's CMW?
Mark Hensler
If there is no answer on Google, then there is no question.
mmi posted this at 15:48 — 8th February 2001.
They have: 457 posts
Joined: Jan 2001
thanks as always for the useful info - my understanding is that ASPs can only run on Windows NT servers and since my provider has those "no longer patchy" ones, I figger I can't do 'em - I kinda expected that there wasn't gonna be a way around the limitations of these wildcards but at least now I KNOW that's the case and I can express an intelligent opinion about an alternative - you really helped me out on this to say the least and I very much appreciate it - CMW is Cooking My Way - ya might wanna check out the navbar's index !!
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Mark Hensler posted this at 07:53 — 10th February 2001.
He has: 4,048 posts
Joined: Aug 2000
looking good
mmi posted this at 04:26 — 4th September 2008.
They have: 457 posts
Joined: Jan 2001
Hey
Like a voice (hopefully not too nightmarish) from the somewhat distant past, I've returned to yer friendly community in an effort to get the little search engine on mmy recipe page working again. It stopped working a few years ago when I moved the code to a different server. Yesterday, I again tried changing the username — and it worked!
Well, I got a result at least. The problem is: the code designed to cause a subset of the recipes to be returned (those with an ingredient matching the string entered in the textbox) isn't functioning. You instead get all the recipes held in the db (currently only about fifteen or so that I've entered for testing).
Here's the search page. Here's the code for results.php
<html><head><title>CMW Search Results for <? echo $ingredient ?></title>
<SCRIPT LANGUAGE=javascript TYPE="text/javascript">
function openCmwWindow(){
cmwWindow=window.open('','cmwWin','menubar=yes,status=yes,scrollbars=no,resizable=yes,width=740,height=420');}
</script>
<STYLE TYPE="text/css"><!--
BODY {font: 10pt Tahoma; color: #fffff0}
SPAN {font: 500 13pt Tahoma; color: #f4c508}
A {font: 600 14pt Tahoma; color:orange; text-decoration:none}
--></style>
</head>
<body bgcolor="#000080" text="#000000" id=all>
<div width="95%" align="right"><a href="http://ememi.com/cmw/realindex.html">another<br>search </a></div>
<?
$db = mysql_connect("localhost", "username","password");
mysql_select_db("mmi_ememicom",$db);
$query = "SELECT * FROM RECIPES WHERE (ing1 LIKE '%$ingredient%') OR (ing2 LIKE '%$ingredient%') OR (ing3 LIKE '%$ingredient%')";
$query .= " AND (ing1 IS NOT NULL) AND (ing2 IS NOT NULL) AND (ing3 IS NOT NULL)";
if (mysql_errno()) { echo mysql_error(); }
$result = mysql_query($query,$db);
if (mysql_num_rows($result) == 0) {
?> <SPAN> <? echo "Sorry, no recipes for that - try another ingredient"; ?> </span>
<?
}
while ($recipe = mysql_fetch_array($result)) {
?>
<a href="<? echo $recipe[href]; ?>" target="cmwWin"><? echo $recipe[recipe]; ?></a>
<a href="<? echo $recipe[href]; ?>" target="cmwWin"><span><? echo $recipe[recipes]; ?></span></a><br><br>
<?
} #END while
?>
</body></html>
Anything jump out as a reason for all recipes being returned?
Thanks!
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mmi posted this at 02:13 — 5th September 2008.
They have: 457 posts
Joined: Jan 2001
I was handed a solution by a colleague:
add $ingredient = $_REQUEST['ingredient'];
WORKS!
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