PHP question

teammatt3 posted this at 23:58 — 10th September 2005.

Joined: Sep 2003

I am trying to get this to work. I have this script... Don't look through it, scroll down to the bottom.

<?php
function google_pagerank($url) {

    /* 
    This code is released unto the public domain 
    Raistlin Majere <a href="mailto:[email protected]" class="bb-email">[email protected]</a> 
    */

    define('GOOGLE_MAGIC', 0xE6359A60);
    
    //unsigned shift right
    function zeroFill($a, $b)
    {
    $z = hexdec(80000000);
    if ($z & $a)
    {
    $a = ($a>>1);
    $a &= (~$z);
    $a |= 0x40000000;
    $a = ($a>>($b-1));
    }
    else
    {
    $a = ($a>>$b);
    }
    return $a;
    }
    
    function mix($a,$b,$c) {
    $a -= $b; $a -= $c; $a ^= (zeroFill($c,13));
    $b -= $c; $b -= $a; $b ^= ($a<<8);
    $c -= $a; $c -= $b; $c ^= (zeroFill($b,13));
    $a -= $b; $a -= $c; $a ^= (zeroFill($c,12));
    $b -= $c; $b -= $a; $b ^= ($a<<16);
    $c -= $a; $c -= $b; $c ^= (zeroFill($b,5));
    $a -= $b; $a -= $c; $a ^= (zeroFill($c,3)); 
    $b -= $c; $b -= $a; $b ^= ($a<<10);
    $c -= $a; $c -= $b; $c ^= (zeroFill($b,15));
    
    return array($a,$b,$c);
    }
    
    function GoogleCH($url, $length=null, $init=GOOGLE_MAGIC) {
    if(is_null($length)) {
    $length = sizeof($url);
    }
    $a = $b = 0x9E3779B9;
    $c = $init;
    $k = 0;
    $len = $length;
    while($len >= 12) {
    $a += ($url[$k+0] +($url[$k+1]<<8) +($url[$k+2]<<16) +($url[$k+3]<<24));
    $b += ($url[$k+4] +($url[$k+5]<<8) +($url[$k+6]<<16) +($url[$k+7]<<24));
    $c += ($url[$k+8] +($url[$k+9]<<8) +($url[$k+10]<<16)+($url[$k+11]<<24));
    $mix = mix($a,$b,$c);
    $a = $mix[0]; $b = $mix[1]; $c = $mix[2];
    $k += 12;
    $len -= 12;
    }
    
    $c += $length;
    switch($len) /* all the case statements fall through */
    {
    case 11: $c+=($url[$k+10]<<24);
    case 10: $c+=($url[$k+9]<<16);
    case 9 : $c+=($url[$k+8]<<8);
    /* the first byte of c is reserved for the length */
    case 8 : $b+=($url[$k+7]<<24);
    case 7 : $b+=($url[$k+6]<<16);
    case 6 : $b+=($url[$k+5]<<8);
    case 5 : $b+=($url[$k+4]);
    case 4 : $a+=($url[$k+3]<<24);
    case 3 : $a+=($url[$k+2]<<16);
    case 2 : $a+=($url[$k+1]<<8);
    case 1 : $a+=($url[$k+0]);
    /* case 0: nothing left to add */
    }
    $mix = mix($a,$b,$c);
    /*-------------------------------------------- report the result */
    return $mix[2];
    }
    
    //converts a string into an array of integers containing the numeric value of the char
    function strord($string) {
    for($i=0;$i<strlen($string);$i++) {
    $result[$i] = ord($string{$i});
    }
    return $result;
    }
    
    function get_pr($url) {
    $result=array(\"\",-1);
    
    if (($url.\"\"!=\"\")&&($url.\"\"!=\"http://\")):
    // check for protocol 
    if (substr(strtolower($url),0,7)!=\"http://\"):
    $url=\"http://\".$url;
    endif;
    
    $url=\"info:\".$url;
    $checksum=GoogleCH(strord($url));
    $google_url=sprintf(\"http://www.google.com/search?client=navclient-auto&ch=6%u&features=Rank&q=\".$url,$checksum); // url to get from google 
    
    $contents=\"\";
    // let's get ranking 
    // this way could cause problems because the Browser Useragent is not set... 
    if ($handle=fopen($google_url,\"rb\")):
    while(true):
    $data=fread($handle,8192);
    if (strlen($data)==0):
    break;
    endif;
    $contents.=$data;
    endwhile;
    fclose($handle);
    else:
    $contents=\"Connection unavailable\";
    endif;
    
    $result[0]=$contents;
    // Rank_1:1:0 = 0 
    // Rank_1:1:5 = 5 
    // Rank_1:1:9 = 9 
    // Rank_1:2:10 = 10 etc 
    $p=explode(\":\",$contents);
    if (isset($p[2])):
    $result[1]=$p[2];
    endif;
    endif;
    
    return $result;
    }
    
    $pr = get_pr($url);
    if($pr[1] == -1)
        $pr[1] = 0;
    return $pr[1];

} // end google_pagerank()
?>

What it does is display pagerank. Now to see the pagerank I use this code

<?php
echo google_pagerank('http://www.nutang.com'); // output: 5
?>

What if the main part of the code is at example.com but I am displaying the short part of the code at example2.com do I do something like

<?php
echo www.example2.com_google_pagerank('http://www.nutang.com'); // output: 5
?>

I have no idea if it's possible to host php scripts on different domains and then call for them.

Renegade posted this at 01:54 — 11th September 2005.

He has: 3,022 posts

Joined: Oct 2002

Yes, it's possible to host PHP scripts on other domains/servers and call them, just use the include function:

<?php
include("http://www.example-domain.com/script.php");
?>

Busy posted this at 11:10 — 11th September 2005.

He has: 6,151 posts

Joined: May 2001

Not sure if you will be able to do it with PHP5 and may also have to remember about safe mode - on or off ...

teammatt3 posted this at 15:54 — 11th September 2005.

He has: 2,102 posts

Joined: Sep 2003

Well, for some reason, the script works on my computer (I have PHP on it) but it doesn't work on the web.

JeevesBond posted this at 16:07 — 11th September 2005.

He has: 3,956 posts

Joined: Jun 2002

phpinfo(); then, check the configurations are the same? Also have you tried Renegades method. It's a little different to yours (although that shouldn't really make any difference you never know...)

And what happens when you try running it on the web? What error pops out?

a Padded Cell our articles site!

teammatt3 posted this at 16:21 — 11th September 2005.

He has: 2,102 posts

Joined: Sep 2003

See for yourself http://koopy.org/pagerank.php

<?php
 // let's get ranking 
    // this way could cause problems because the Browser Useragent is not set... 
(line 108)    if ($handle=fopen($google_url,\"rb\")):
(line 109)    while(true):
(line 110)    $data=fread($handle,8192);
?>