how to echo this line of code??
i want to display this line out...
<? include ("$url_site/template/index.php?cat_ID=$cat_ID");?>but it seems that it will include the file but not displaying the line of the code, how can i do it??
i tried this :
<?php
echo \" include (\"$url_site/template/index.php?cat_ID=$cat_ID\");\";
?>also not working..
pls help...
i would like it to place in here:
<?php
print \"<tr bgcolor=#9999ff height=50><td align=center><font face=\\"Verdana\\" color=\\"#ffffff\\" size=2><b>PLACE IT HERE!</b></font></td></tr></table><br>\n\";
?>
Busy posted this at 21:04 — 11th December 2001.
He has: 6,151 posts
Joined: May 2001
Do you just want to line without the contents?
echo 'url_site/template/index.php?cat_ID=$cat_ID';
or the other way is to use the html code for a '<' which is < and '>' is >
I'm still pretty new to this but where you want to include it may be easier over 3 lines
print "";
print =. "PLACE IT HERE!";
print =. "\n";
good luck
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