CGI Include
Just wandering,
In php, to include a file you use the command
include("filename.ect");
What (if anything) would be the perl equivalent to that?
Thanks for the help,
TheSpaceDude
[email protected]
http://www.thespacezone.com
Just wandering,
In php, to include a file you use the command
include("filename.ect");
What (if anything) would be the perl equivalent to that?
Thanks for the help,
TheSpaceDude
[email protected]
http://www.thespacezone.com
japhy posted this at 15:51 — 20th October 2000.
They have: 161 posts
Joined: Dec 1999
You probably want the require() function, or perhaps the do() function. Be warned, files included into your program should end with the line
1;because Perl expects them to return a true value (that indicates success).
fairhousing posted this at 02:26 — 21st October 2000.
They have: 1,587 posts
Joined: Mar 1999
yeah, require will probably do it for u.
Suzanne posted this at 04:00 — 21st October 2000.
She has: 5,507 posts
Joined: Feb 2000
require "file.txt";
require "file2.txt";
require "files.txt";
Most scripts and programmers recommend you have it near the top of the script/program, before the variables, for ease.
P.S. This was edited to correct my brain fart, thank you!
[Edited by Suzanne on 10-21-2000 at 03:23 AM]
japhy posted this at 04:03 — 21st October 2000.
They have: 161 posts
Joined: Dec 1999
No, Suzanne, I'm afraid you can't. require() takes at most one argument, and that argument MUST be the name of a module, or the path to a single file to be included. To include several files at once, make an array of them, and require each element of the array separately:
# pre-5.005 code
for (@files) { require }
# 5.005 and later
require for @files;
Mark Hensler posted this at 04:35 — 21st October 2000.
He has: 4,048 posts
Joined: Aug 2000
How 'bout this:
require "text1.txt","text2.txt";
like:
print "this","and","this";
japhy posted this at 11:22 — 21st October 2000.
They have: 161 posts
Joined: Dec 1999
No, trust me. require does not take a list of files. perldoc -f require
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