automatic fill of day field
How do I create a function that will automatically fill my "day" field (on my database file) with 3-char such as 'Mon', 'Tue', etc depending on what day it gets from a linux system? Something like the following only alpha-formatted on my day .
$time1 = @_[0];
($time1) or ($time1 = time());
my ($sec, $min, $hour, $day, $mon, $year, $dweek, $dyear, $daylight) = localtime(time());
my (@months) = qw!Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec!;
($day < 10) and ($day = "0$day");
$year = $year + 1900;
return "$day-$months[$mon]-$year";
Suzanne posted this at 18:54 — 16th November 2000.
She has: 5,507 posts
Joined: Feb 2000
How entertaining!
You need to make a list of the days and map them over so that $days[0] = Sunday or whatever.
Rob Pengelly posted this at 20:56 — 16th November 2000.
They have: 850 posts
Joined: Jul 1999
Are you just trying to get the current day? If so try using:
my $time = substr(localtime(),0,3);
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