Javascript Rollover - rollover does not function cleanly

Thanks John,
If you get a chance, it would be appreciated!

Thanks again

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Alan Izat

The onMoueout command in the link tag doesn't make a call to a fuvtion to switch back the image. It just calls one that removes a message from the status bar. I only saw a function for the initial switch.

If I get a chance, I'll see if I can add that in for you.

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John Pollock
http://www.pageresource.com

First of all never trust the JavaScript generated by web design programs - you should always type it yourself for best results.

If you follow my code below, you will need to re-type a fair bit of your existing code.

1.Add this code between the HEAD tags

<script language="JavaScript">
<!-- hide script from old browsers

// DECLARE THE 3 DIFFERENT STATES OF YOUR BUTTON
// DO SO FOR ALL YOUR IMAGES (6?)
if (document.images) {
NAME_over = new Image(); NAME_over.src = "URL";
NAME_out = new Image(); NAME_out.src = "URL";
NAME_down = new Image(); NAME_down.src = "URL";
}

// THESE FUNCTIONS CALL THE DIFFERENT IMAGES FOR EACH STATE THAT THE BUTTON CAN BE
// WHERE THE STUPID FACES APPEAR, THEY SHOULD BE CLOSING BRACKETS eg. )

function mouseOver(imgName) {
if (document.images) {
document[imgName].src=eval(imgName + "_over.src");
}
}

function mouseOut(imgName) {
if (document.images) {
document[imgName].src=eval(imgName + "_out.src");
}
}

function mouseDown(imgName) {
if (document.images) {
document[imgName].src=eval(imgName + "_down.src");
}
}

// end hiding from old browsers -->
</script>

2.Use this code for your images

<a href="URL"
onMouseOver="mouseOver('NAME')"
onMouseOut="mouseOut('NAME')"
onMouseDown="mouseDown('NAME')"
onMouseUp="mouseOver('NAME')"><img
src="URL"
name="NAME"
border="0" height="" width=""></a>

Notes:
-Make sure you give a unique name to each image

Now I have not tested this script but if you give it a go and still have trouble, just reply again to this discussion or email me

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[email protected]
vegas.com.au/~jasper

Thanks for the help. I will give it a shot...I'll post how it goes.

Alan Izat

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Alan Izat